$32^{x-3}$ x $8^{x+4}$ = $\frac{64}{2^x}$
$2^{5(x-3)}$ x $2^{3(x+4)}$ = $2^6 \times (2)^{-x}$
5x - 15 + 3x + 12 = 6 - x
8x - 3 = 6 - x
9x = 9;
x = 1
johnmulu answered the question on June 12, 2017 at 08:12
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Solve for x
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June 12, 2017
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June 12, 2017
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June 12, 2017
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Date posted:
June 9, 2017
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Date posted:
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Date posted:
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Date posted:
June 9, 2017
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Answers (1)
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Date posted:
June 9, 2017
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Answers (1)